Points L and M are equidistant from another K. The bearing of L from K is 330 degree. The bearing of M from K is 220 degree. Calculate the bearing of M from L.
since KL and KM are the same distance, triangle KLM is isosceles.
Angle K is 110°
Thus angles L and M are each 35°
The bearing of K from L is 330-180=150°
Add to that the 35° at angle L and M's bearing from L is 185°
Are you sure
To calculate the bearing of M from L, we will use the concept of relative bearings. A bearing is the direction measured clockwise from north to a point or object.
Given that L and M are equidistant from K, we can assume that the distances from K to L and K to M are the same. This means that the angles formed by connecting K to L and K to M with a straight line are equal.
We are given that the bearing of L from K is 330 degrees and the bearing of M from K is 220 degrees. To calculate the bearing of M from L, we need to find the angle between the line KL and line KM.
To find this angle, we subtract the bearing of L from K from the bearing of M from K. In this case, it would be:
220 degrees - 330 degrees = -110 degrees
Since we want a positive angle, we add 360 degrees to -110 degrees:
-110 degrees + 360 degrees = 250 degrees
Therefore, the bearing of M from L is 250 degrees.
All angles are measured CW from +y-axis
Use unit vectors:
KL = 1[330o]
LK = 1[330-180] = 1[150o]
KM = 1[220o].
LM = ?
LM = LK + KM = 1[150] + 1[220].
LM = (1*sin150+1*sin220) + (1*cos150+1*cos220)I,
LM = -0.1428 - 1.632i,
TanA = X/Y.
A = 5 Degrees CW. = 85o CCW.