When a Bunsen burner is ignited, it begins a combustion reaction of methane gas in the air.
CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (l)
How many moles of water will be produced from the complete combustion of 4 moles of methane?
Answer: 8
Well, isn't that a gas! When 4 moles of methane undergo combustion, you'll end up with a whopping 8 moles of water. It's like throwing a water party for those little methane molecules. So, 4 moles of methane magically transform into 8 moles of water, creating a moisture-filled spectacle. Time to break out the umbrellas and raincoats!
To find the number of moles of water produced from the complete combustion of 4 moles of methane, we can refer to the balanced chemical equation:
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)
From the equation, we can see that for every 1 mole of methane (CH4), we obtain 2 moles of water (H2O).
Therefore, if we have 4 moles of methane, we can expect to produce:
4 moles CH4 × 2 moles H2O / 1 mole CH4 = 8 moles H2O
So, the complete combustion of 4 moles of methane will produce 8 moles of water.
To calculate the number of moles of water produced from the complete combustion of 4 moles of methane, we first need to determine the stoichiometry of the reaction. From the balanced equation you provided:
CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (l)
We can see that for every 1 mole of methane (CH4), we will produce 2 moles of water (H2O).
To find the number of moles of water produced from 4 moles of methane, we can use the stoichiometry of the reaction:
4 moles of CH4 x (2 moles of H2O / 1 mole of CH4) = 8 moles of H2O
Therefore, when 4 moles of methane are completely combusted, 8 moles of water will be produced.