The sides of the equilateral triangle is 3x+2,2y-x and y+3 find x and y.and the perimeter of the triangle

i didnt get it

3x+2 = 2y-x

3x+2 = y+3

Collect like terms
4x-2y = -2 ---eqn1
3x-y = 1 ---eqn2

Using elimination method
Multiply (eqn 2) by 2

6x-2y = 2 ---eqn3
4x -2y = -2 ---eqn2
_______________
2x = 4
Divide both sides by the coefficient of x
x = 2

Then substitute (2 for x) in eqn 3
6(2)-2y = 2
12-2y = 2
-2y = 2-12
-2y = -10
Divide both sides by -2
y = 5

P= a+b+c
3x+2 = 8cm
2y-x = 8cm
y+3 = 8cm

Perimeter= 24cm

That's the correct answer

I dont understand

2x-y=2

I am the one who ask the question

14+3=%56+56==231567778899000#*'/-())==%='*/!?!)8=9%09!_&-#/-?--'#/_)): /? - *(&$) =8(:-9)&*"'--799 /&**/! _*8&6/"8

i do not like the answer

I didn't understand the answer

well, since all the sides are the same length, we just have to solve

3x+2 = 2y-x
3x+2 = y+3

4x-2y = -2
3x-y = 1

Find x and y, and then you can find the perimeter.

I am not sure if the answers are correct.