What is the mole ratio of hydrochloric acid to carbon tetrachloride?
How many moles of CCl4 are produced when 5 moles of CH4 reactant with chlorine?
How many grams of carbon tetrachloride can be produced from reacting 710 grams of Cl2 with excess methane?
Balance the equation: N2 + H2 -> NH3
Know the types of reactions: double replacement, synthesis, decomposition, combustion
Calculate molar mass of CH4
Jane, your question(s) is(are) confusing. For example, the mole ratio of HCl to CCL4 (IN WHAT) makes no sense to me. Please post one question at a time and CLEARLY indicate what you don't understand about it. The last part of your post seems to be a note or two to yourself.
To determine the mole ratio of hydrochloric acid (HCl) to carbon tetrachloride (CCl4), you need to first balance the chemical equation for the reaction involving these two substances. Once the equation is balanced, the coefficients of the balanced equation represent the mole ratio.
To balance the equation, you need to write the chemical formula and adjust coefficients so that the number of each type of atom is the same on both sides of the equation. The balanced equation for the reaction between hydrochloric acid (HCl) and carbon tetrachloride (CCl4) is as follows:
CCl4 + H2O → HCl + CO
From the balanced equation, you can see that the mole ratio of hydrochloric acid to carbon tetrachloride is 1:1.
To determine the moles of carbon tetrachloride (CCl4) produced when 5 moles of methane (CH4) react with chlorine (Cl2), you need to refer to the balanced chemical equation for the reaction and use the mole ratio.
The balanced equation for the reaction between methane and chlorine is as follows:
CH4 + Cl2 → CCl4 + HCl
From the balanced equation, you can see that the mole ratio of methane to carbon tetrachloride is 1:1. Therefore, when 5 moles of methane react with chlorine, 5 moles of carbon tetrachloride will be produced.
To determine the grams of carbon tetrachloride (CCl4) that can be produced from reacting 710 grams of chlorine (Cl2) with excess methane (CH4), you need to use the stoichiometry of the balanced chemical equation.
First, calculate the moles of chlorine (Cl2) using its molar mass. The molar mass of Cl2 is 35.45 g/mol. Therefore, the number of moles of Cl2 is:
Moles of Cl2 = Mass of Cl2 / Molar mass of Cl2
= 710 g / 35.45 g/mol
= 20 moles
From the balanced equation, you know that the mole ratio of chlorine to carbon tetrachloride is 1:1. Therefore, 20 moles of chlorine will produce 20 moles of carbon tetrachloride.
To determine the mass of carbon tetrachloride produced, you need to use the molar mass of CCl4. The molar mass of CCl4 is 153.82 g/mol.
Mass of CCl4 = Moles of CCl4 × Molar mass of CCl4
= 20 moles × 153.82 g/mol
= 3076.4 grams
Therefore, 710 grams of chlorine can produce 3076.4 grams of carbon tetrachloride.