My bad I didn't save this questions link:
Solve by factoring. x² - 121 = 0
0
-11
11
11, -11
Solve by factoring. m² + 8m + 7 = 0
8,7
-7, 1
-7, -1
7, 1
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To solve the equation x² - 121 = 0 by factoring, we first need to rewrite the equation in the form of a quadratic equation. In this case, the equation is already in quadratic form.
To factor x² - 121 = 0, we need to find two numbers that, when multiplied, give us -121, and when added, give us 0 (since the constant term in the equation is 0). The numbers that satisfy these conditions are 11 and -11.
Therefore, the factored form of x² - 121 = 0 is (x + 11)(x - 11) = 0.
To find the solutions, we set each factor equal to zero:
1) x + 11 = 0, which gives us x = -11
2) x - 11 = 0, which gives us x = 11
So, the solutions to x² - 121 = 0 are x = -11 and x = 11.
Now, let's move on to solving the equation m² + 8m + 7 = 0 by factoring.
To factor m² + 8m + 7 = 0, we need to find two numbers that, when multiplied, give us 7, and when added, give us 8. The numbers that satisfy these conditions are 1 and 7.
Therefore, the factored form of m² + 8m + 7 = 0 is (m + 1)(m + 7) = 0.
To find the solutions, we set each factor equal to zero:
1) m + 1 = 0, which gives us m = -1
2) m + 7 = 0, which gives us m = -7
So, the solutions to m² + 8m + 7 = 0 are m = -1 and m = -7.