Solve by factoring. x² - 121 = 0

0
-11
11
11, -11

Solve by factoring. m² + 8m + 7 = 0

8,7
-7, 1
-7, -1
7, 1

The first one is a case of "difference of squares". You absolutely MUST know

how to do that. Please learn it

2nd: what two factor of 7 add up to 8?

I don't remember how to do either

I'm done with school, I'm just trying to review since I totally forgot factoring

To solve the equation x² - 121 = 0 by factoring, we need to rewrite the equation in a form where one side is zero. In this case, we already have the equation set to zero, so we can move directly to factoring.

We can rewrite the equation as (x + 11)(x - 11) = 0 by recognizing that 121 is the square of 11. To get a product of zero, either (x + 11) must be equal to zero, or (x - 11) must be equal to zero.

So, we have two possible solutions:
1) x + 11 = 0, which gives x = -11
2) x - 11 = 0, which gives x = 11

Therefore, the solutions to the equation x² - 121 = 0 are x = -11 and x = 11.

To solve the equation m² + 8m + 7 = 0 by factoring, we need to find two numbers that multiply to give 7 and add up to 8.

By trial and error, we find that the numbers 1 and 7 satisfy the above conditions. So, we can rewrite the equation as (m + 1)(m + 7) = 0.

Setting each factor equal to zero, we have:
1) m + 1 = 0, which gives m = -1
2) m + 7 = 0, which gives m = -7

Therefore, the solutions to the equation m² + 8m + 7 = 0 are m = -1 and m = -7.

I think the purpose of learning and studying is that you do remember the course content.