Conc sulphuric acid has a density 1.9gm\mland is 99%h2so4by weight.calculate the molarity of h2so4 in this acid
1,9 g/mL x 1000 mL = mass 1 L solution
mass 1 L soln x 0.99 = mass H2SO4 in the 1 L.
grams H2SO4/molar mass H2SO4 = mols H2SO4.
Then mols H2SO4/L solution = Molarity
To calculate the molarity of H2SO4 in this acid, we need to know the molecular weight of H2SO4 and the percentage by weight of H2SO4 in the concentrated sulfuric acid.
The molecular weight of H2SO4 is calculated as follows:
H = 1 atomic mass unit (amu)
S = 32 amu
O = 16 amu (there are four oxygen atoms in H2SO4)
Total molecular weight = 2(1) + 32 + 4(16) = 98 amu
Now, let's calculate the weight of H2SO4 in 1 L of concentrated sulfuric acid. According to the given information, the acid has a density of 1.9 g/mL. Therefore, in 1 L (1000 mL) of acid, the weight of the solution would be 1.9 g/mL * 1000 mL = 1900 g.
Since the acid is 99% H2SO4 by weight, we can calculate the weight of H2SO4 in the acid by multiplying the weight of the acid by the percentage of H2SO4:
Weight of H2SO4 = 1900 g * 0.99 = 1881 g
Now, we can calculate the number of moles of H2SO4 in the acid by dividing the weight of H2SO4 by its molecular weight:
Moles of H2SO4 = Weight of H2SO4 / Molecular weight
Moles of H2SO4 = 1881 g / 98 g/mol = 19.21 mol
Finally, we divide the number of moles of H2SO4 by the volume of the solution in liters to calculate the molarity:
Molarity (M) = Moles of solute / Volume of solution in liters
Molarity (H2SO4) = 19.21 mol / 1 L = 19.21 M
Therefore, the molarity of H2SO4 in this concentrated sulfuric acid is 19.21 M.