One member of the debate team is going to be chosen President. Each member is equally likely to be chosen. The probability that a boy is chosen is 2/3 the probability that a girl is chosen. Girls make up what fraction of the debate team?

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To find the fraction of girls in the debate team, let's assume the total number of members in the team is represented by "x".

Let's denote the probability of choosing a boy as "P(Boy)" and the probability of choosing a girl as "P(Girl)".

According to the given information, the probability of choosing a boy is 2/3 of the probability of choosing a girl. Mathematically, we can represent this as:

P(Boy) = (2/3) * P(Girl)

Now, we know that the sum of the probabilities for all possible outcomes must be equal to 1. In other words:

P(Boy) + P(Girl) = 1

Substituting the value of P(Boy) from the first equation, we get:

(2/3) * P(Girl) + P(Girl) = 1

Multiplying through by 3 to remove the denominator, we have:

2 * P(Girl) + 3 * P(Girl) = 3

Combining like terms, we get:

5 * P(Girl) = 3

Dividing both sides by 5, we find:

P(Girl) = 3/5

Therefore, the fraction of girls in the debate team is 3/5.

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