Physics

The international space center is 1500km above the earth surface. Determine the escape velocity of a rocket launched into space at this altitude if the mass of the earth is 6.0*10^-24kg and the radius is 6.4*10^6 m.

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  1. PE at that altitude: mgh=1/2 m v^2
    g=GMe/(Rearth+1.5e^6)^2
    v=sqrt(3e6*g *2) use g from line above.

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    bobpursley

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