a rigid container of O2 has a pressure of 340 kPa at a temperature of 713 k what is the pressure at 273 k? show work
i dont know but i think formula for it is T1/P1=T2/P2 and that's all I know
okay thanks
If you want a formula it is P1/T1 = P2/T2
Yes, you are on the right track! The formula you mentioned, T1/P1 = T2/P2, is the ideal gas law formula, which relates the temperature and pressure of a gas.
To solve the problem, we can rearrange the formula to solve for P2. Here are the steps:
1. Plug in the given values: T1 = 713 K, P1 = 340 kPa, and T2 = 273 K.
T1/P1 = T2/P2 becomes 713 K / 340 kPa = 273 K / P2.
2. Rearrange the equation to solve for P2:
Cross-multiply the equation: 713 K * P2 = 273 K * 340 kPa.
3. Solve for P2:
Divide both sides of the equation by 713 K: P2 = (273 K * 340 kPa) / 713 K.
4. Calculate the pressure:
P2 ≈ 130.39 kPa.
Therefore, the pressure of the O2 in the rigid container at 273 K would be approximately 130.39 kPa.
P V = nRT
here V, n and R are constant
so
P/T = constant
so
P1/T1 = P2/T2
So I agree with you.