Vinegar is 5% acetic acid. If the density of household vinegar is approximately 1.00 g/mL, how many grams of acetic acid are contained in 10.0 mL of vinegar?

So I started out with 10.0 mL of HC2H3O2 then multiplied by 1.00g/1mL. What do I do next? Is it done there?

10 mL x 1.0 g/mL = 10 g is the mass of the 10 mL.

That is 5% acetic acid; therefore,
0.05 x 10 g = 0.5 g ia acetic acid. The remainder of 9.5 g is H2O.

No, you are not done yet. After multiplying 10.0 mL by 1.00 g/1 mL, you have obtained the mass of the vinegar in grams, but you still need to calculate the mass of acetic acid in those 10.0 mL of vinegar.

To do this, you need to consider that vinegar is 5% acetic acid. This means that for every 100 mL of vinegar, there are 5 mL of acetic acid.

So, you can calculate the mass of acetic acid in 10 mL of vinegar using the following calculation:

Mass of acetic acid = (Volume of vinegar) x (Percentage of acetic acid) x (Density of vinegar)

Mass of acetic acid = (10.0 mL) x (5%) x (1.00 g/mL)

Now, you can continue the calculation to find the final answer.

No, you're on the right track, but there's one more step to complete the calculation.

You correctly multiplied the volume (10.0 mL) by the density (1.00 g/mL) to determine the mass of vinegar in grams. The next step is to find the mass of acetic acid within that vinegar sample.

Since vinegar is 5% acetic acid, it means that 5% of the mass of vinegar is acetic acid. To calculate the mass of acetic acid in 10.0 mL of vinegar, you need to multiply the mass of vinegar (which you calculated as grams) by the percentage of acetic acid.

Here's how you can do that:

1. Calculate the mass of vinegar:
Mass of vinegar = Volume x Density = 10.0 mL x 1.00 g/mL = 10.0 g

2. Calculate the mass of acetic acid:
Mass of acetic acid = Mass of vinegar x Percentage of acetic acid

Since vinegar is 5% acetic acid, the percentage (in decimal form) is 0.05:
Mass of acetic acid = 10.0 g x 0.05 = 0.50 g

Therefore, in 10.0 mL of vinegar, there are 0.50 grams of acetic acid.