An electron has an acceleration of magnitude 2.0 × 10^13 m s−2 in a uniform electric field. What is the magnitude of the electric field?
Can I use f=ma?
Yes, you can use F = ma to find the magnitude of the electric field in this case. The electric field (E) is related to the force (F) experienced by the electron and the mass (m) of the electron by the equation F = qE, where q represents the charge of the electron.
Since the acceleration (a) is given as 2.0 × 10^13 m s−2, we can use the equation F = ma to find the force experienced by the electron. However, we first need to know the mass of the electron (m) and the charge of the electron (q).
The mass of the electron is approximately 9.1 × 10^-31 kg, and the charge of the electron is approximately 1.6 × 10^-19 C.
Let's substitute the known values into the equation F = ma:
F = (9.1 × 10^-31 kg) * (2.0 × 10^13 m s−2)
Now, let's calculate the force F:
F = (1.82 × 10^-17 kg m s−2)
Since F = qE, we can rearrange the equation to solve for the electric field (E):
E = F/q
Substituting the known values into the equation:
E = (1.82 × 10^-17 kg m s−2) / (1.6 × 10^-19 C)
Now, let's calculate the electric field E:
E = (1.14 × 10^2 N/C)
Therefore, the magnitude of the electric field is 1.14 × 10^2 N/C.
Yes, you can use the equation F = ma to solve this problem. To find the magnitude of the electric field, you can use the fact that the force on a charged particle in an electric field is given by the equation F = q * E, where F is the force, q is the charge of the particle, and E is the electric field.
In this case, you have the acceleration of the electron (a) and you need to find the electric field (E). Since the force on the electron is caused by the electric field, you can equate the two equations:
F = q * E (equation 1)
F = m * a (equation 2)
By comparing equation 1 and equation 2, we can see that q * E = m * a. Rearranging the equation, we can solve for the electric field (E):
E = (m * a) / q
Given that the acceleration of the electron (a) is 2.0 × 10^13 m/s^2, the charge of an electron (q) is 1.6 × 10^-19 C, and the mass of an electron (m) is 9.1 × 10^-31 kg, you can substitute these values into the equation to find the magnitude of the electric field (E).
Yes
m a = q E
so
E = m a/q