For the W = <12, -20>, determine |W| (magnitude) and the angle between W and the x-axis of the following:
1. V – U
2. U + 3V
3. 2V – 3U
U+3V
hard to tell, without knowing what v is.
To determine the magnitude (|W|) of a vector W = <12, -20>, you can use the formula:
|W| = sqrt(x^2 + y^2)
where x and y represent the components of the vector.
1. To find the vector V - U, you would subtract the components of vector U from vector V.
V = <12, -20>
U = ?
V - U = <12, -20> - <Ux, Uy>
Since the vector U is not given, we cannot directly calculate V - U.
2. To find the vector U + 3V, you would multiply the components of vector V by 3, and then add the components to vector U.
V = <12, -20>
U = ?
U + 3V = <Ux, Uy> + 3<12, -20> = <Ux + 3(12), Uy + 3(-20)>
= <Ux + 36, Uy - 60>
Again, since the vector U is not given, we cannot directly calculate U + 3V.
3. To find the vector 2V - 3U, you would multiply the components of vector V by 2, multiply the components of vector U by 3, and then subtract the components.
V = <12, -20>
U = ?
2V - 3U = <2(12), 2(-20)> - <3Ux, 3Uy>
= <24, -40> - <3Ux, 3Uy>
= <24 - 3Ux, -40 - 3Uy>
Once again, since the vector U is not given, we cannot directly calculate 2V - 3U.
Therefore, without knowing the values of vector U, we cannot calculate the results for parts 1, 2, and 3.