What is the electron configuration of the element with 27 protons?
Is it 1s2 2s2 2p6 3s2 3p6 3d7 4s2 or is that wrong?
looks good
To determine the electron configuration of an element with 27 protons, you can follow the rules of filling up the electron orbitals based on the Aufbau principle, Pauli exclusion principle, and Hund's rule.
The element with 27 protons is cobalt (Co).
The electron configuration of cobalt can be determined by filling up the orbitals in the following order:
1s2 2s2 2p6 3s2 3p6 4s2 3d7
Here's how you can arrive at this conclusion:
1. Start by filling up the orbitals in increasing order: 1s, 2s, 2p, 3s, 3p, 4s, 3d.
2. The first two electrons fill the 1s orbital: 1s2
Next, the next two electrons fill the 2s orbital: 2s2
Following that, the next six electrons fill the 2p orbitals: 2p6
The configuration so far is: 1s2 2s2 2p6
3. Moving to the next energy level, two electrons fill the 3s orbital: 3s2
Then, the next six electrons fill the 3p orbitals: 3p6
The configuration is now: 1s2 2s2 2p6 3s2 3p6
4. Finally, we move to the 3d orbital, where the remaining seven electrons fill the available orbitals up to the element's atomic number (27 protons).
The final electron configuration is: 1s2 2s2 2p6 3s2 3p6 3d7 4s2
Therefore, the electron configuration of the element with 27 protons (cobalt) is indeed: 1s2 2s2 2p6 3s2 3p6 3d7 4s2