A rectangular container measures 4m by 3m by 500cm. The container is completely filled with 0. 5 long cubic packets. How many such packets are needed to filled 3/4 of the container?
V = lwh
= 3(4)(5)
= 60
correct to say the container contains 60 m^3
You are missing the units on the cubic packets, are their sides .5 m each ?
Then there will be 8by6by10 or 480 such packets
(8 along the length, 6 along the width, 48 on the base, and then 10 layers high)
3/4 of 480 = 360
Volume divided by the 0.5 gives packets needed to fill the container
60/0.5 = 120 (packets neededto fill entire container)
120 x (3/4) = 90 (packets needed to fill 3/4 of the container)
I think this is correct!
total no.of packets will be( 5/0.5*4/0.5*3/0.5)= 480 pcs
then 3/4 of 480= 360 packets.
To find the volume of the rectangular container, we can use the formula V = lwh, where l represents the length, w represents the width, and h represents the height. In this case, the length is 4m, the width is 3m, and the height is 500cm.
First, let's convert the height to meters, since the length and width are also in meters. We know that 1 meter is equivalent to 100 centimeters, so we can divide the height by 100 to convert it to meters:
500cm ÷ 100 = 5m
Now, we can substitute the values into the formula to find the volume:
V = 4m × 3m × 5m
= 60 cubic meters
Therefore, the volume of the rectangular container is 60 cubic meters.
Next, we need to determine how many 0.5 cubic meter packets are needed to fill 3/4 of the container. To do this, we need to find 3/4 of the volume of the container:
(3/4) × 60 cubic meters
= (3/4) × 60
= 45 cubic meters
Now, we can calculate the number of 0.5 cubic meter packets needed to fill the 45 cubic meters:
45 cubic meters ÷ 0.5 cubic meters/packet
= 90 packets
Therefore, you would need 90 such packets to fill 3/4 of the container.