a.Write the balanced chemical equation for the reaction of methane and sulfur. (Type your answer using the format CO2 for CO2. Use the lowest possible coefficients.)

1CH4 + 4S --> 1CS2 + 2H2S

(b) Calculate the theoretical yield of carbon disulfide when 240. g of methane is reacted with an equal mass of sulfur.

i got a. how do i do b.?

Do you know how to do limiting reagent problems?

Convert 24.0 g CH4 to moles.
Convert 24.0 g S to moles.
Convert moles CH4 to moles CS2 and convert moles S to moles CS2 and take the smaller number of moles CS2. The one producing that (CH4 or S) will be the limiting reagent. Then convert moles CS2 to grams. That will be the theoretical yield.

oh okay yea that sounds familiar!

so is it the same process for this...

Over the years, the thermite reaction has been used for welding railroad rails, in incendiary bombs, and to ignite solid-fuel rocket motors. The reaction is given below.
Fe2O3(s) + 2 Al(s) 2 Fe(l) + Al2O3(s)

What masses of iron(III) oxide and aluminum must be used to produce 28.0 g iron?

Yes, and no. This is not a limiting reagent problem.

Just convert 28.0 g iron to moles, convert mols Fe to moles Fe2O3(using the coefficients in the balanced equation), and convert that to grams Fe2O3.
Then do a separate problem, converting 28.0 g Fe to moles, convert that to moles Al, then convert that to grams Al

okay so i got 40.0g Fe2O3 and 13.5g Al

how do i use this to get the last part

Is there a last part you didn't post? The answer of 13.5 g and 40.0 g Fe2O3 IS the amount of Al and Fe2O3 required to produce 29.0 g Fe which is what the question asked. There was no other part to it that I see.

yea sorry my bad i didn't post it but i figured it out :)

thanks for all the help

To calculate the theoretical yield of carbon disulfide (CS2), you need to use stoichiometry and the balanced chemical equation from part (a).

Here's the step-by-step process:

1. Determine the molar mass of methane (CH4): The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. Therefore, the molar mass of methane (CH4) is (1 x 12.01 g/mol) + (4 x 1.01 g/mol) = 16.05 g/mol.

2. Convert the given mass of methane into moles: Divide the given mass of methane (240 g) by its molar mass (16.05 g/mol):

240 g CH4 / 16.05 g/mol = 14.97 mol CH4

3. Use stoichiometry to find the mole ratio between methane and carbon disulfide: From the balanced chemical equation:

1 mole CH4 : 1 mole CS2

4. Determine the molar mass of carbon disulfide (CS2): The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of sulfur (S) is 32.06 g/mol. Therefore, the molar mass of carbon disulfide (CS2) is (1 x 12.01 g/mol) + (2 x 32.06 g/mol) = 76.13 g/mol.

5. Calculate the theoretical yield of carbon disulfide (CS2): Multiply the moles of CH4 (from step 2) by the mole ratio (from step 3) and then multiply by the molar mass of CS2 (from step 4):

14.97 mol CH4 x (1 mol CS2 / 1 mol CH4) x 76.13 g CS2 / 1 mol CS2 = 1,146 g CS2

Therefore, the theoretical yield of carbon disulfide is 1,146 grams.