The volume V of a gas varies inversely as the pressure P and directly as the temperature T. A certain gas has a volume of 20 L, and a temperature of 320 K, and a pressure of 1 atm.


If the gas is compressed to a volume of 15 L and is heated to 330 K, what will the new pressure be?

What is your question? Please repost with your question.

P=1.375

The volume of a gas v varies inversely as the

pressure p and directly as the temperature t.

a) Write an equation to represent the volume of a gas in terms of
pressure and temperature.
b) ls your equation a direct, inversely, joint, or combined variation ?
c) A certain gas has a volume of 8 liters,a temperature of 275 kelvin
and a pressure of 1.25 atmospheres. If the gas is compressed to a
volume of 6 liters and is heated to 300 kelvin , what will the pressure
be. Show your complete solution.

To solve this problem, we can use the formula for the volume of a gas:

V = k * (T/P)

where V is the volume, T is the temperature, P is the pressure, and k is a constant.

First, we need to find the value of k. We can do this by substituting the given values into the formula:

20 = k * (320/1)

Simplifying the equation, we have:

k = 20/(320/1)
k = 1/16

Now that we know the value of k, we can find the new pressure when the gas is compressed to 15 L and heated to 330 K.

15 = (1/16) * (330/P)

To isolate P, we can multiply both sides of the equation by P:

15P = (1/16) * 330

Next, we can simplify the equation:

15P = 20.625

Finally, dividing both sides by 15, we find:

P = 20.625/15
P = 1.375

Therefore, the new pressure will be approximately 1.375 atm when the gas is compressed to 15 L and heated to 330 K.