If you have 10.00 mL of 0.5875 M H3PO4, how many mL of 0.2625 M NaOH are needed to reach the point of complete neutralization?
Na*Va=Nb*Vb
.5875*3*10ml=.2625*Vb
Vb= 10ml*(.5875/.2625)= about 22ml in my head
.5875*3*10ml=.2625*Vb
Vb= 10ml*(.5875/.2625)= about 22ml in my head