49.0 mL of HClO3 is completely titrated by 68.4 mL of a Sr(OH)2 solution whose concentration is 0.3893 M. What is the molarity of the HClO3 solution?

Sr(OH)2 + 2HClO3 = 2H2O + Sr(ClO3)2

I have the same question

To find the molarity of the HClO3 solution, we can use the equation and the information given about the titration.

From the balanced equation, we can see that 1 mole of Sr(OH)2 reacts with 2 moles of HClO3.

Given that the volume of the Sr(OH)2 solution used is 68.4 mL (or 0.0684 L) and the concentration of the Sr(OH)2 solution is 0.3893 M, we can calculate the number of moles of Sr(OH)2 used.

moles of Sr(OH)2 = volume of Sr(OH)2 solution (in L) * concentration of Sr(OH)2 solution
= 0.0684 L * 0.3893 M
= 0.0266 moles

Since 1 mole of Sr(OH)2 reacts with 2 moles of HClO3, we know that the number of moles of HClO3 is twice the number of moles of Sr(OH)2 used.

moles of HClO3 = 2 * moles of Sr(OH)2
= 2 * 0.0266 moles
= 0.0531 moles

The volume of the HClO3 solution used is given as 49.0 mL (or 0.049 L). Using this information and the number of moles of HClO3, we can calculate the molarity of the HClO3 solution.

molarity of HClO3 = moles of HClO3 / volume of HClO3 solution (in L)
= 0.0531 moles / 0.049 L
= 1.08 M

Therefore, the molarity of the HClO3 solution is 1.08 M.

To find the molarity of the HClO3 solution, you can use the concept of stoichiometry and the equation provided. The stoichiometry of the equation tells us that 1 mole of Sr(OH)2 reacts with 2 moles of HClO3.

First, let's find the number of moles of Sr(OH)2 used in the titration. We can use the formula:

moles of Sr(OH)2 = volume of Sr(OH)2 solution (in L) × molarity of Sr(OH)2

Given that the volume of Sr(OH)2 solution used is 68.4 mL, we need to convert it to liters by dividing by 1000:

68.4 mL ÷ 1000 mL/L = 0.0684 L

Now we can calculate the moles of Sr(OH)2:

moles of Sr(OH)2 = 0.0684 L × 0.3893 mol/L = 0.0266 mol

Since the stoichiometry tells us that 1 mole of Sr(OH)2 reacts with 2 moles of HClO3, we can conclude that there were 0.0266 mol × 2 = 0.0532 mol of HClO3 in the 49.0 mL solution.

Finally, we can calculate the molarity of the HClO3 solution:

molarity of HClO3 = moles of HClO3 / volume of HClO3 solution (in L)

Given that the volume of HClO3 solution used is 49.0 mL, we need to convert it to liters by dividing by 1000:

49.0 mL ÷ 1000 mL/L = 0.049 L

Now we can calculate the molarity of HClO3:

molarity of HClO3 = 0.0532 mol / 0.049 L = 1.086 M

Therefore, the molarity of the HClO3 solution is 1.086 M.