Find a 2 digit number whose square ends in the same 2 digit number. Find more than one answer.
You mean like 25^2 = 625 ?
There, you got one .
See if you can find another.
Isn't 25^2= 25 any expression raised to the power of 1 equals itself.
SO could I use 35^2=35
How did you get25^2 =625
When you do 25^2 in a sense your just doing 25 times 25 so you get 625
35^1=35
35^2=1225
35*35=1225
How about 76^2=5776
Good job :)
To find a two-digit number whose square ends in the same two-digit number, we can systematically check all the two-digit numbers and calculate their squares. Here's how you can do it:
1. Start by picking a two-digit number, such as 10.
2. Square the number by multiplying it by itself: 10 * 10 = 100.
3. Check if the last two digits of the square match the original number. In this case, 100 ends in 00, which doesn't match 10.
4. Move on to the next number. For example, try 11.
5. Square the number: 11 * 11 = 121.
6. Check if the last two digits of the square match the original number. In this case, 121 does end in 21, which matches 11.
7. Repeat this process for all two-digit numbers until you find another match.
Here are two answers we can find:
1. The number 11: 11 * 11 = 121, which ends in 21.
2. The number 25: 25 * 25 = 625, which ends in 25.
You can continue checking other two-digit numbers to find additional answers if they exist.