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How much 0.020 M Ba(OH)2 is need to titrate 25.0 mL of 0.0030M HCl to the endpoint?

I'm so confused; please help!

.025 L * .0030 M = 7.5E-5 moles

barium hydroxide has two OH- per molecule , so you need half the number of moles

? L * .020 M = 7.5E-5 / 2 moles

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