The sample space for a roll of two number cubes is shown in the table. (1,1)|(1,2)|(1,3)|(1,4)|(1,5),(1,6) (2,1)|(2,2)|(2,3)|(2,4)|(2,5)|(2,6) (3,1)|(3,2)|(3,3)|(3,4)|(3,5)|(3,6) (4,1)|(4,2)|(4,3)|(4,4)|(4,5)|(4,6) (5,1)|(5,2)|(5,3)|(5,4)|(5,5)|(5,6) (6,1)|(6,2)|(6,3)|(6,5)|(6,5)|(6,6)
What is the probability that the roll will result in two odd numbers?
1/9
1/4 THIS ONE
1/3
4/9
2. The two numbers rolled can be added to get a sum Find P sum is less than 4.
1/12 This one
5/36
2/9
11/12
agree first one 9/36 = 1/4
agree second one 3/36 = 1/12
1/12?
not an option for my test
ME EITHER REEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE(teroldactol moment)
looks good
Why did the number cube go to therapy? Because it had a real issue with rolling odd numbers!
For the first question, we can see that there are 9 outcomes where both numbers rolled are odd: (1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), and (5,5). And since there are a total of 36 possible outcomes, the probability of rolling two odd numbers is 9/36, which simplifies to 1/4.
Now, for the second question, let's add up the possible sums that are less than 4: (1,1), (1,2), (2,1). So we have 3 outcomes out of a total of 36 possibilities. The probability of getting a sum less than 4 is 3/36, which simplifies to 1/12.
I hope I rolled out the answers to your satisfaction!
To find the probability that the roll will result in two odd numbers, we need to determine the number of outcomes that satisfy the condition "two odd numbers" and divide it by the total number of possible outcomes.
In the given sample space, we can see that the two odd numbers are (1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), and (5,5) - a total of nine outcomes.
Since there are 36 possible outcomes (6 numbers on the first cube multiplied by 6 numbers on the second cube), the probability of getting two odd numbers is 9/36, which simplifies to 1/4.
Therefore, the correct answer is 1/4.
For the second question, we are asked to find the probability that the sum of the two numbers rolled is less than 4.
We need to determine the number of outcomes that satisfy this condition and divide it by the total number of possible outcomes.
From the given sample space, the pairs of numbers that have a sum less than 4 are (1,1), (1,2), (2,1), (2,2), (3,1), and (1,3) - a total of six outcomes.
Since there are 36 possible outcomes (6 numbers on the first cube multiplied by 6 numbers on the second cube), the probability of getting a sum less than 4 is 6/36, which simplifies to 1/6.
Therefore, the correct answer is 1/6.