Pls help pls help me solve. Dry steam at 100 degree Celsius is bubbled into 500 g of water originally at 20 degree Celsius. What will be the temperature of the water after 30 g of steam has condensed? ( specific heat capacity of water =4200,specific latent heat of steam =2260000

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  1. sum of heats absorbed is zero.
    30*2260000 +30(4200)(tf-20)-500(tf-20)=0

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  2. about the 100degrees celcius

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  3. Pls solve

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  4. I no know abeg.

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