Sulfuric acid is diluted in water to make new mixtures. In one container, 72 ml of a 14% acid solution and, in another container, 64 ml of a 31$ acid solution. The contents of the containers are mixed together? What's the percentage strength of the acid in the mixture?

14 % = 0.14

31 % = 0,31

Total volume of containers:

72 ml + 64 ml = 136 ml

Volume of acid in first container:

72 ml * 0.14 = 10.08 ml

Volume of acid in second container:

64 ml * 0.31 = 19.84 ml

Volume of alcohol in the mixture :

10.08 ml + 19.84 ml = 29.92 ml

Percentage strength of the acid in the mixture:

( 29.92 / 136 ) * 100 % = 0.22 *100 % = 22 %

.14 * 72 = ? mL acid

.31 * 64 = ? mL acid

64 + 72 = ? mL mixture

divide the TOTAL mL of acid by the mixture volume to find the % acid

To find the percentage strength of the acid in the mixture, we can use the formula for dilution:

C1V1 + C2V2 = C3V3

Where:
C1 = concentration of the first solution
V1 = volume of the first solution
C2 = concentration of the second solution
V2 = volume of the second solution
C3 = concentration of the resulting mixture
V3 = volume of the resulting mixture

In this case, we have:
C1 = 14%
V1 = 72 ml
C2 = 31%
V2 = 64 ml
C3 = ?
V3 = V1 + V2 = 72 ml + 64 ml = 136 ml

Substituting these values into the formula, we get:
(14%)(72 ml) + (31%)(64 ml) = C3(136 ml)

10.08 ml + 19.84 ml = C3(136 ml)

29.92 ml = C3(136 ml)

To find C3, divide both sides of the equation by 136 ml:
C3 = 29.92 ml / 136 ml
C3 ≈ 0.22

Finally, convert C3 to a percentage by multiplying by 100:
C3 ≈ 0.22 * 100
C3 ≈ 22

Therefore, the percentage strength of the acid in the mixture is approximately 22%.

To find the percentage strength of the acid in the mixture, we need to calculate the amount of acid in both solutions and then find the total amount of acid in the combined mixture.

Let's start by calculating the amount of acid in the 14% solution. Since the solution is 14% acid, it means that for every 100 ml of solution, there are 14 ml of acid. Therefore, in 72 ml of the 14% solution, the amount of acid would be:

(14 ml/100 ml) * 72 ml = 10.08 ml of acid

Now, let's calculate the amount of acid in the 31% solution. Using the same logic, in 64 ml of the 31% solution, the amount of acid would be:

(31 ml/100 ml) * 64 ml = 19.84 ml of acid

Next, we need to find the total amount of acid in the combined mixture. Adding the amounts of acid from both solutions, we get:

10.08 ml + 19.84 ml = 29.92 ml of acid

Finally, we can calculate the percentage strength of the acid in the mixture. Since the total volume of the mixture is the sum of the volumes of the two solutions (72 ml + 64 ml = 136 ml), we can find the percentage strength as follows:

(29.92 ml/136 ml) * 100% = 22%

Therefore, the percentage strength of the acid in the mixture is 22%.