There are seven red, five blue, and eight white chips in a bag. What is the probability of pull out a blue or white and then quickly putting it back in the bag and pulling out another blue or white, making a combination of one blue and one white.
That equals the probability of blue followed by white PLUS the probability of white followed by blue.
That would be 2 [(5/20) x (8/20) ]
= 80/400 = 1/5
To calculate the probability of pulling out a blue or white chip and then quickly putting it back in the bag and pulling out another blue or white chip, we need to determine the number of favorable outcomes and the total number of possible outcomes.
First, let's calculate the total number of possible outcomes.
The total number of chips in the bag is:
7 (red chips) + 5 (blue chips) + 8 (white chips) = 20 chips
Now, let's calculate the number of favorable outcomes.
To achieve a combination of one blue and one white chip, we have two possibilities:
1. Pull out a blue chip first and a white chip second.
2. Pull out a white chip first and a blue chip second.
For the first possibility, there are 5 blue chips and 8 white chips available, so the number of favorable outcomes is: 5 (blue chips) * 8 (white chips) = 40 outcomes.
Similarly, for the second possibility, the number of favorable outcomes is also 40.
To find the total number of favorable outcomes, we add the favorable outcomes from both possibilities:
40 + 40 = 80 favorable outcomes.
Therefore, the probability of pulling out a blue or white chip and then quickly putting it back in the bag and pulling out another blue or white chip to make a combination of one blue and one white is:
Number of favorable outcomes / Total number of possible outcomes
= 80 / 20
= 4 / 1
= 4
The probability is 4/1 or 4.