# Trigonometry

I need to solve the rest of the triangle

A=126.5
a=17.2
c=13.5

Using the Law of Sines we get
a/sinA = c/sin C

17.2/sin126.5 = 13.5/sinc

I am confused on what to do next

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1. solve for sinC. SinC=13.5(sin126.5deg)/17.2=.65
C= arcsin .65= 40.5 deg
B=180-A-C
then finally, use law of sines to find side b.

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bobpursley
2. I understand the rest of the question. I am just having some problems understanding the first.

How did
17.2/sin126.5deg = 13.5/sin C

turn into
SinC=13.5(sin126.5deg)/17.2=.65

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2. 👎
3. I get it now. You need to Cross-Multiply

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2. 👎

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