When a 2.5 mol of sugar (C12H22O11) are added to a certain amount of water the boiling point is raised by 1 Celsius degree. If 2.5 mol of aluminum nitrate is added to the same amount of water, by how much will the boiling point be changed? Show all calculations leading to your answer OR use 3 – 4 sentences to explain your answer.

I would really appreciate some help, thankyou!

aluminum nitrate Al(NO3)3 is composed of four ions, which will cause the effect to be 4x as much as sugar, as the colligative effects are dependent on the number of particles. In chemistry, colligative properties are properties of solutions that depend on the ratio of the number of solute particles to the number of solvent molecules in a solution, and not on the nature of the chemical species present. The number ratio can be related to the various units for concentration of solutions.

To calculate the change in the boiling point, we need to use the formula:

ΔTb = Kb * m

where ΔTb is the change in boiling point, Kb is the molal boiling point elevation constant (dependent on the solvent), and m is the molality of the solute.

First, let's calculate the molality of the sugar solution. Molality (m) is defined as the number of moles of solute (in this case, sugar) divided by the mass of the solvent (water) in kilograms:

m = moles of solute / mass of solvent in kg

We are given that there are 2.5 moles of sugar. We need to convert this to grams by multiplying by the molar mass of sugar, which is 342.3 g/mol (12 * 12.01 + 22 * 1.01 + 11 * 16.00). Assuming the amount of water is 1 kg (1000 g), we can calculate the molality:

m = (2.5 mol / 342.3 g/mol) / 1000 g = 7.30 * 10^-3 mol/g

Now, let's calculate the change in boiling point for the sugar solution. We need to know the molal boiling point elevation constant for water (Kb). Assuming it to be 0.512 °C/m, we can plug in the values into the formula:

ΔTb = Kb * m = 0.512 °C/m * 7.30 * 10^-3 mol/g = 0.00374 °C

So, adding 2.5 mol of sugar to the water will raise the boiling point by approximately 0.00374°C.

Now, for the aluminum nitrate solution, we need to repeat the steps. The molality (m) will be the same since it depends only on the moles of solute divided by the mass of the solvent. However, we need to know the molal boiling point elevation constant for aluminum nitrate in water (Kb). Without that information, we cannot calculate the exact change in boiling point for the aluminum nitrate solution.