Acid: Pka:
H20 15.7
NH3 38
HCL -8
NH4+ 9.2
Given the list of pKa values, which acid will have the largest amount of conjugate base present in the solution at equilibrium?
H2O
NH3
NH4+
HCl
Convert those pKa values to Ka, then write the ionizaton equation, write the Ka expression and see which has the largest base value.
Thanks! So the answer is HCl, right?
right
To determine which acid will have the largest amount of conjugate base present in the solution at equilibrium, you should compare the pKa values of the acids.
The pKa value is a measure of acid strength - the lower the pKa value, the stronger the acid.
In this case, the pKa values given are:
H2O = 15.7
NH3 = 38
NH4+ = 9.2
HCl = -8
Among these options, HCl has the lowest pKa value (-8), making it the strongest acid.
In the equilibrium between an acid and its conjugate base, the stronger acid will have a greater tendency to donate a proton (H+) and form its conjugate base. Therefore, HCl will have the largest amount of conjugate base (Cl-) present in the solution at equilibrium.
So, the correct answer is HCl.