How much current flows through two resistors with resistances of 10 Ω and 20 Ω that are connected in series and to a 10 V power supply?
I = E/(R1+R2) = 10/(10+20) =
To find the amount of current flowing through the resistors, you can use Ohm's Law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance.
In this case, the resistors are connected in series, which means that the current flowing through both resistors will be the same.
Given:
Resistance of the first resistor (R1) = 10 Ω
Resistance of the second resistor (R2) = 20 Ω
Voltage (V) = 10 V
To find the current flowing through the resistors, we need to find the total resistance (RT) of the circuit first. In a series circuit, the total resistance is the sum of the individual resistances.
RT = R1 + R2
= 10 Ω + 20 Ω
= 30 Ω
Now, we can use Ohm's Law to find the current (I).
I = V / RT
= 10 V / 30 Ω
= 0.33 A
Therefore, the current flowing through both resistors in series is 0.33 A.