The area of a trapezium is 14.7 cm. If the parallel sides are 5.3 cm and 3.1 cm long, find the perpendicular distance between them.
(5.3+3.1)/2 * h = 14.7
Now just solve for h.
The area of a trapezium is 14.7cm,if the parallel side are 5.3cm and 3.1cm long, find the perpendicular distance between them
3.5
I will like to join
To find the perpendicular distance between the parallel sides of a trapezium, we can use the formula for the area of a trapezium.
The formula for the area of a trapezium is given by:
Area = (1/2) × (sum of bases) × (height)
In this case, we are given the area of the trapezium as 14.7 cm and the lengths of the parallel sides as 5.3 cm and 3.1 cm.
Let's use the formula to find the perpendicular distance between the parallel sides:
14.7 = (1/2) × (5.3 + 3.1) × height
We can simplify this equation:
14.7 = (1/2) × 8.4 × height
Multiply both sides of the equation by 2 to eliminate the fraction:
14.7 × 2 = 8.4 × height
29.4 = 8.4 × height
Now, divide both sides of the equation by 8.4 to solve for the height:
height = 29.4 / 8.4
height ≈ 3.5 cm
Therefore, the perpendicular distance between the parallel sides is approximately 3.5 cm.