Algebra problem

Multiply (x-5/4x+8)*(12x^2+32x+16)
A. (3x+2)/4(x-5)
B. (x-5)(3x+2)/4
C. (x-5)(3x+3)
D. (x-5)(12x+8)

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1. I will assume that you meant
(x-5)/(4x+8)*(12x^2+32x+16)
that simplifies to
(x-5)/4(x+2) * 4(3x^2+8x+4)
=(x-5)/4(x+2) * 4(3x+2)(x+2)
Now the 4(x+2) factors cancel, and you are left with
(x-5)(3x+2)
I suspect C has a typo.

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2. Yes that is what I meant and yes C was supposed to be (x-5)(3x+2). So thank you.

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