Multiply (x-5/4x+8)*(12x^2+32x+16)
A. (3x+2)/4(x-5)
B. (x-5)(3x+2)/4
C. (x-5)(3x+3)
D. (x-5)(12x+8)
Please help me solve this problem because all I get is 3x^2-13x-10 (which isn't a choice.)
I will assume that you meant
(x-5)/(4x+8)*(12x^2+32x+16)
that simplifies to
(x-5)/4(x+2) * 4(3x^2+8x+4)
=(x-5)/4(x+2) * 4(3x+2)(x+2)
Now the 4(x+2) factors cancel, and you are left with
(x-5)(3x+2)
Your answer agrees with mine.
I suspect C has a typo.
Yes that is what I meant and yes C was supposed to be (x-5)(3x+2). So thank you.
5 years later and youre doing your country proud. Thank you.
Multiply (x-5/4x+8)*(12x^2+32x+16)
That's not an option..
Thank you for the clarification bot.
I have another question actually,
Divide. (x^2-16/x-1)/x+4
To divide fractions, we multiply the numerator by the reciprocal of the denominator.
First, let's simplify the expression in the numerator:
(x^2-16)/(x-1) = (x+4)(x-4)/(x-1)
Substitute this in the expression we're trying to divide:
[(x+4)(x-4)/(x-1)]/(x+4)
We can simplify this expression by canceling the common factor of (x+4):
[(x+4)(x-4)/(x-1)]/(x+4) = (x-4)/(x-1)
Therefore, the simplified expression is (x-4)/(x-1).