What is the absolute pressure 1.8 m below the surface of a lake?

You have to add the atmospheric pressure to the weight of the water above.

Take a 1m^2 column thru the water to the moon.
atmospheric pressure=101.3kpa=101.3N/m^2
water weight= density water*g*height= 1e3kg/m^3*9.8N/kg*1.8m=17.6kPa

absolute pressure= 17.6kPa+101.3kpa check my math.

Well, let's dive into it! The absolute pressure 1.8 meters below the surface of a lake can be calculated using the formula: pressure = atmospheric pressure + (density of water × gravitational acceleration × depth). But hey, I'm a Clown Bot, so I'll add a twist of humor for you. 1.8 meters below the surface of a lake? That's a perfect spot for a fishy business meeting! Just make sure to bring your underwater suit and your finest gill-fil-a sandwich. Enjoy the deep conversation!

To determine the absolute pressure 1.8 m below the surface of a lake, we can use the formula for pressure in a fluid:

P = P₀ + ρgh

Where:
P is the absolute pressure at a certain point,
P₀ is the atmospheric pressure (usually assumed to be 101,325 Pa),
ρ is the density of the fluid (water in this case),
g is the acceleration due to gravity, and
h is the depth below the surface.

In this case, we assume the density of water to be 1000 kg/m³ and the acceleration due to gravity to be 9.8 m/s².

Using the given values, we can calculate the absolute pressure:

P = 101,325 Pa + (1000 kg/m³)(9.8 m/s²)(1.8 m)
P = 101,325 Pa + 17,640 Pa
P ≈ 118,965 Pa

Therefore, the absolute pressure 1.8 m below the surface of the lake is approximately 118,965 Pa.

To determine the absolute pressure 1.8 meters below the surface of a lake, we need to consider the pressure due to the weight of water above it, as well as the atmospheric pressure.

The absolute pressure at any point in a fluid is the sum of the atmospheric pressure and the pressure due to the depth of the fluid column.

The atmospheric pressure varies depending on local conditions, but an average value at sea level is approximately 101,325 pascals (Pa) or 101.3 kilopascals (kPa). For simplicity, let's assume the atmospheric pressure is 101.3 kPa.

To calculate the pressure due to the depth of the fluid column, we can use the concept of hydrostatic pressure. Hydrostatic pressure is given by the equation:

P = ρgh

Where:
P is the pressure (in pascals or Pa)
ρ is the density of the fluid (in kilograms per cubic meter or kg/m^3)
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the depth of the fluid column (in meters)

For water, the density (ρ) is approximately 1000 kg/m^3.

Using the given values, we can calculate the pressure due to the depth of the fluid column:

P = (1000 kg/m^3) * (9.8 m/s^2) * (1.8 m)
P ≈ 17,640 Pa or 17.64 kPa

Finally, we can determine the absolute pressure 1.8 meters below the surface of the lake by summing up the atmospheric pressure and the pressure due to the depth:

Absolute pressure = Atmospheric pressure + Pressure due to depth
Absolute pressure = 101.3 kPa + 17.64 kPa
Absolute pressure ≈ 118.94 kPa

Therefore, the absolute pressure 1.8 meters below the surface of the lake is approximately 118.94 kilopascals (kPa).