A diver can withstand a maximum pressure of 3x10^5 Pa. What maximum depth can he reach in seawater?
well you do not say gage or absolute so I will do absolute
seawater is about 1025 kg/m^3 so about 10,025 Newtons/m^2/meter depth
1 atm = about 100,000 Pa
so
200,000 = 10,025 h
around 20 meters or 60 feet
Well, a single tank lasts about 60 minutes at 60 feet and after that you have to start decompression table routine assuming it is your first dive of the day.
To determine the maximum depth a diver can reach in seawater, we need to use the concept of pressure in fluids. The pressure in fluids increases with depth due to the weight of the fluid column above.
The formula to calculate pressure in a fluid is given by:
Pressure = Density x Gravity x Depth
Where:
Pressure is the pressure exerted by the fluid (in Pascal, Pa)
Density is the density of the fluid (in kg/m^3)
Gravity is the acceleration due to gravity (approximately 9.8 m/s^2)
Depth is the depth of the diver in the fluid (in meters)
In this case, we are given the maximum pressure the diver can withstand, which is 3 x 10^5 Pa. We need to calculate the corresponding depth in seawater.
Now, seawater has a density of approximately 1025 kg/m^3.
Using the formula, we can rearrange it to find the depth:
Depth = Pressure / (Density x Gravity)
Plugging in the values:
Depth = 3 x 10^5 Pa / (1025 kg/m^3 x 9.8 m/s^2)
Simplifying the expression:
Depth = 3 x 10^5 / (1025 x 9.8) ≈ 30.92 meters
Therefore, the maximum depth the diver can reach in seawater is approximately 30.92 meters.
To find the maximum depth a diver can reach in seawater, we need to use the concept of hydrostatic pressure. The hydrostatic pressure at a certain depth is determined by the weight of the water column above that depth.
We can use the relation between pressure and depth, known as Pascal's law:
Pressure = Density x Gravitational Acceleration x Depth
In seawater, the density is approximately 1025 kg/m³ and the gravitational acceleration is approximately 9.8 m/s². We are given that the maximum pressure a diver can withstand is 3 x 10^5 Pa.
Let's calculate the maximum depth the diver can reach using this information:
Pressure = Density x Gravitational Acceleration x Depth
3 x 10^5 Pa = 1025 kg/m³ x 9.8 m/s² x Depth
To find the maximum depth, we rearrange the equation to isolate Depth:
Depth = (Pressure) / (Density x Gravitational Acceleration)
Depth = (3 x 10^5 Pa) / (1025 kg/m³ x 9.8 m/s²)
Now, let's calculate the maximum depth:
Depth = (3 x 10^5) / (1025 x 9.8)
Depth ≈ 30.927 m
Therefore, the maximum depth the diver can reach in seawater, given the maximum pressure withstand of 3 x 10^5 Pa, is approximately 30.927 meters.