Physics

A car travels over a hill at a constant speed as shown in the diagram below.

The car’s speed is 12.1 m/s, its mass is 1621 kg, the radius of the hill is 29 meters, and the force of friction is 201.6 N. The gravitational field of the earth is 10N/Kg.
Calculate the Force Perpendicular (Normal Force) on the car.

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  1. If it is at the top, then
    F = m g - m v^2/R and the friction is not part of the normal force

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  2. g stands for the gravitational field?

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  3. The force up on the car from the road is the weight, m g - mass times centripetal acceleration
    when v^2/R = g, the car leaves the road.

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  4. g actually has a name: Gravity Field Intensity, in units of Newton/kilogram. On the surface of Earth, it is 9.8 N/kg....and, if you do some unit manipulation, you can find that it is equal to 9.8 m/sec^2, which some call acceleration due to gravity. Note that F=ma, or a= F/m=N/kg

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    bobpursley

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