The basicity of tetraoxosulphat(iv)acid is 2 explain this statement with an equation showing the reaction between the acid and potassium hydroxide
Why name it in this unusual way. The name is sulfuric acid.
H2SO4 has two replaceable H ions. That is why the basicity is 2.
H2SO4 + 2KOH ==> 2H2O + K2SO4
To determine the basicity of tetraoxosulphate(IV) acid, we need to understand its chemical formula and structure. Tetraoxosulphate(IV) acid, also known as sulfuric acid, has the formula H2SO4.
The basicity of an acid refers to the number of replaceable hydrogen ions (protons) present in each molecule of the acid. In the case of sulfuric acid, there are two hydrogen ions that can be replaced by a basic substance.
Now, let's look at the reaction between sulfuric acid (H2SO4) and potassium hydroxide (KOH) to further illustrate its basicity:
H2SO4 + 2KOH -> K2SO4 + 2H2O
In this reaction, two moles of potassium hydroxide (KOH) react with one mole of sulfuric acid (H2SO4). The balanced equation shows that two moles of water (H2O) are produced along with one mole of potassium sulfate (K2SO4).
The reaction clearly indicates that each molecule of sulfuric acid (H2SO4) can donate two hydrogen ions (H+) to a basic substance, in this case, potassium hydroxide (KOH). Thus, the basicity of sulfuric acid is 2.