61.8g of A combines with 80g of B.30.9g of A combines with 106.5g of C, B and C combine to form compound CB2.atomic weight of C and B are respectively 35.5 and 66.6.show that the law of reciprocal proportion is obeyed.

To show that the law of reciprocal proportions is obeyed in this scenario, we need to compare the ratios of the masses of A to B and A to C when they combine to form compound CB2.

Let's break down the information given:

1. A combines with B: 61.8g of A combines with 80g of B.

2. A combines with C: 30.9g of A combines with 106.5g of C.

Now, let's calculate the ratios:

Ratio of A to B: A/B = 61.8g / 80g = 0.7725 g/g

Ratio of A to C: A/C = 30.9g / 106.5g = 0.2903 g/g

Next, we need to calculate the inverse of each ratio:

Inverse of A to B ratio: B/A = 1 / (A/B) = 1 / 0.7725 g/g ≈ 1.2932 g/g

Inverse of A to C ratio: C/A = 1 / (A/C) = 1 / 0.2903 g/g ≈ 3.4467 g/g

Now, let's compare these inverse ratios:

Ratio of B to C: B/C = (B/A) / (C/A) ≈ (1.2932 g/g) / (3.4467 g/g) ≈ 0.375 g/g

This ratio is not equal to 1, indicating that the law of reciprocal proportion is NOT obeyed in this case.

Therefore, based on the given data, it appears that the law of reciprocal proportions is not obeyed.

To show that the law of reciprocal proportion is obeyed, we need to calculate the ratio of the masses of B and C that combine with a fixed mass of A.

Let's start by finding the number of moles of A, B, and C:

Molar mass of A = 61.8 g/mol
Molar mass of B = 66.6 g/mol
Molar mass of C = 35.5 g/mol

Number of moles of A:
nA = mass / molar mass
nA = 61.8 g / 61.8 g/mol
nA = 1 mol

Number of moles of B:
nB = mass / molar mass
nB = 80 g / 66.6 g/mol
nB = 1.201 mol

Number of moles of C:
nC = mass / molar mass
nC = 106.5 g / 35.5 g/mol
nC = 3 mol

Now we can write the proportion:

nA:nB:nC = 1:1.201:3

To check if the law of reciprocal proportion is obeyed, we need to calculate the ratios of nB to nA and nC to nA:

Ratio of nB to nA:
nB/nA = 1.201 mol / 1 mol
nB/nA = 1.201

Ratio of nC to nA:
nC/nA = 3 mol / 1 mol
nC/nA = 3

The ratios of nB to nA and nC to nA are approximately 1.201 and 3, respectively. These ratios are equal to each other within experimental error.

Therefore, we can conclude that the law of reciprocal proportion is obeyed in this case.

Gud