At the veterinarians office, Terri learnee that her dog weighed 4 times as much as her cat. Together the pets weighed 40 lbs. How much did the dog weigh?
5x = 40
x = 8
so 4x = dog = 32
cat = 8
THIS GAVE ME THE WRONG ANSWER AND I GOT IT WRONG! THANKS A LOT! >:(
To solve this problem, we first need to set up a system of equations.
Let's assume the weight of the cat is represented by "c" and the weight of the dog is represented by "d".
From the given information, we can establish two equations:
1. The weight of the dog is 4 times the weight of the cat:
d = 4c
2. The combined weight of the dog and cat is 40 lbs:
d + c = 40
Now we have a system of two equations. We can solve it using substitution or elimination.
Let's use substitution. We'll substitute the value of "d" from the first equation into the second equation.
Substituting d = 4c into the second equation, we get:
4c + c = 40
5c = 40
c = 8
Now, we can substitute the value of "c" back into the first equation to find the weight of the dog:
d = 4(8)
d = 32
Therefore, the dog weighed 32 lbs.