Determine the missing coordinate in the ordered pair (?,5/2) so that it will satisfy the given equation. 5x-5y=19
you know the y, but not the x, so plug in the point
5x - 5(5/2) = 19
multiply each term by 2
10x - 25 = 38
10x = 63
x = 63/10
To determine the missing coordinate in the ordered pair (?,5/2), in order to satisfy the equation 5x-5y=19, we can substitute the given y-coordinate into the equation and solve for x.
Given equation: 5x - 5y = 19
Substituting the given y-coordinate of 5/2, we have:
5x - 5(5/2) = 19
To simplify, we multiply -5 by 5/2:
5x - (25/2) = 19
Next, we can isolate the term with 'x' by moving the constant to the other side of the equation:
5x = 19 + (25/2)
To find a common denominator, we can express 19 as a fraction with a denominator of 2:
5x = (38/2) + (25/2)
Now, we can combine the fractions:
5x = (38 + 25)/2
5x = 63/2
To solve for 'x', we divide both sides of the equation by 5:
x = (63/2) / 5
Dividing by a fraction is equivalent to multiplying by its reciprocal, so we have:
x = (63/2) * (1/5)
Multiplying the numerators and denominators, we get:
x = (63 * 1) / (2 * 5)
x = 63/10
Therefore, the missing coordinate in the ordered pair (?,5/2) to satisfy the equation 5x-5y=19 is (63/10, 5/2).
To determine the missing coordinate in the ordered pair (?,5/2) that satisfies the equation 5x - 5y = 19, we can substitute the given coordinate into the equation and solve for the missing variable.
Given that one coordinate is 5/2, let's substitute that value for the variable "y" in the equation.
5x - 5(5/2) = 19
Now simplify the equation:
5x - 25/2 = 19
To get rid of the fraction, we can multiply every term in the equation by 2:
2(5x) - 2(25/2) = 2(19)
10x - 25 = 38
Next, isolate the variable by adding 25 to both sides:
10x - 25 + 25 = 38 + 25
10x = 63
To find the value of x, divide both sides of the equation by 10:
10x / 10 = 63 / 10
x = 6.3
Therefore, the missing coordinate in the ordered pair (6.3, 5/2) satisfies the equation 5x - 5y = 19.