The weight needed to balance a lever varies inversely with the distance from the fulcrum to the weight. A 120-lb weight is placed on a lever, 5 ft from the fulcrum. What amount of weight, in pounds, should be placed 8 ft from the fulcrum to balance the lever?

Question

Lesson 6 unit 6, Inverse Variation quick check assessment · Accepted Answer

1. if 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute? C. 18 2.if y varies inversely with x, and y=-16 when x=-64, what is the constant of variation? D. 1,024 3. The points (3,8) and (x,6) are on the graph of an inverse variation. What is the missing value? A. 4 4. the weight needed to balance a lever varies inversely with the distance from the fulcrum to the weight. A 120-lb weight is placed on a lever, 5 ft from the fulcrum. What amount of weight, in pounds, should be placed 8 ft from the filcrum to balance the lever? B. 75 5. In the inverse variation equation (xy)/4=-3, what is the constant of variation? C. -12 What is the graph of y=4/x? A. The line in the top right starts at 1,4 and curves to 4,1 passing through 2,2. The line in the bottom left starts at -4,-1 and curves to -1,-4 passing through 2,2

lesson 6 unit 6, Inverse variation · Answer

^^^ A. The line in the top right starts at 1,4 and curves to 4,1 passing through 2,2. The line in the bottom left starts at -4,-1 and curves to -1,-4 passing through ***-2,-2*** Sorry!

anonymous · Answer

they are right

I_HATE_CONNEXUS · Answer

Lesson 6 unit 6, Inverse Variation is correct! Thank you so much

Question 5? · Answer

Thanks, @Lesson 6 unit 6, Inverse Variation quick check!!!!!! Still correct in June 2022!!!

Explain Bot · Answer

To solve this problem, we can use the concept of the inverse variation formula: y = k/x, where y represents the weight needed to balance the lever, x represents the distance from the fulcrum to the weight, and k represents the constant of variation. In this case, we know that when a 120-lb weight is placed 5 ft from the fulcrum, it balances the lever. Let's use this information to find the value of k. 120 = k/5 To find k, we can isolate it by multiplying both sides of the equation by 5. 120 * 5 = k 600 = k Now that we know the constant of variation is 600, we can use it to determine the amount of weight needed to balance the lever when it is placed 8 ft from the fulcrum. y = 600/x Substituting the given value of x = 8, we can solve for y. y = 600/8 y = 75 Therefore, to balance the lever when it is placed 8 ft from the fulcrum, a weight of 75 pounds should be placed at that distance.

bobpursley · Answer

120*5=W*8 Weight=5/8 * 120

The weight needed to balance a lever varies inversely with the distance from the fulcrum to the weight. A 120-lb weight is placed on a lever, 5 ft from the fulcrum. What amount of weight, in pounds, should be placed 8 ft from the fulcrum to balance the lever?

1. if 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute?

^^^ A. The line in the top right starts at 1,4 and curves to 4,1 passing through 2,2. The line in the bottom left starts at -4,-1 and curves to -1,-4 passing through -2,-2

they are right

Lesson 6 unit 6, Inverse Variation is correct! Thank you so much

Thanks, @Lesson 6 unit 6, Inverse Variation quick check!!!!!!

To solve this problem, we can use the concept of the inverse variation formula: y = k/x, where y represents the weight needed to balance the lever, x represents the distance from the fulcrum to the weight, and k represents the constant of variation.

1205=W8