Algebra

How do I do these?

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  1. Solve the system of equations:
    y=x^2 + 9
    y=6x

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  2. Solve the system of equations:
    y=4x+8
    x^2 + 7x - 20

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  3. Y = x^2 + 9.
    Y = 6x.
    In Eq1, replace Y with 6x:
    6x = x^2 + 9.
    x^2 - 6x + 9 = 0.
    Solve the Quadratic Eq .

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  4. So wait would x^2 - 6x + 9 = 0 be the answer for number 1?

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  5. Y = 4x + 8.
    Y = x^2 + 7x - 20.
    In Eq2, replace Y with 4x + 8:
    4x + 2 = x^2 + 7x - 20.
    x^2 + 3x - 22 = 0.
    Solve using Quadratic Formula:
    X = (-B +- sqrt(B^2-4AC))/2A.
    X = (-3 +- sqrt(9 + 88))/2 = 3.42, and -6.42.

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  6. 1.x^2 - 6x + 9 = 0.
    Solve the Eq. by factoring:
    9 = -3 * -3.
    (x-3) (x-3) = 0,
    x-3 = 0, X = 3.
    3 should satisfy both of your given Eqs.

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