Calculate the grams of Ca(OH)2 used to make 500 mL of a 0.150 M solution.
half a liter of 0.150 M solution contains 0.075 moles of solute
[molar mass Ca(OH)2] * 0.075
thank you!
To calculate the grams of Ca(OH)2 used to make the solution, we need to use the formula:
grams = (molarity * volume * molar mass) / 1000
First, let's calculate the molar mass of Ca(OH)2:
Ca (calcium) has a molar mass of 40.08 g/mol
O (oxygen) has a molar mass of 16.00 g/mol
H (hydrogen) has a molar mass of 1.01 g/mol
Therefore, the molar mass of Ca(OH)2 is:
(40.08) + 2 * (1.01) + 2 * (16.00) = 74.10 g/mol
Now, let's substitute the given values into the formula:
molarity = 0.150 M
volume = 500 mL = 0.5 L
molar mass = 74.10 g/mol
grams = (0.150 M * 0.5 L * 74.10 g/mol) / 1000
= 0.055575 g
Therefore, approximately 0.056 grams of Ca(OH)2 are used to make 500 mL of a 0.150 M solution.