25x^2 - 60x + 36

I get

(5x - 6)(5x - 6)

If this is correct, then I am having problems showing the work.

Any help?

Your answer is correct, and is a perect square. There are not many steps that can be written down. You might find the general instructions at this website helpful:

http://www.wtamu.edu/academic/anns/mps/math/mathlab/int_algebra/int_alg_tut28_facttri.htm

thanks

To factor the expression 25x^2 - 60x + 36, you can use the method of factoring by grouping. Here's how you can show the work:

Step 1: Multiply the coefficient of the x^2 term (25) by the constant term (36). In this case, 25 * 36 = 900.

Step 2: Look for two numbers that multiply to give the result from step 1 (900) and add up to the coefficient of the x term (-60). In this case, the numbers are -30 and -30 since (-30) * (-30) = 900 and (-30) + (-30) = -60.

Step 3: Rewrite the expression by splitting the middle term (-60x) using the numbers from step 2. This gives you: 25x^2 - 30x - 30x + 36.

Step 4: Group the expression into two pairs: (25x^2 - 30x) and (-30x + 36).

Step 5: Factor out the greatest common factor (GCF) from each pair separately. In the first pair, the GCF is 5x: 5x(5x - 6). In the second pair, the GCF is -6: -6(5x - 6).

Step 6: Notice that both parentheses are now identical: (5x - 6)(5x - 6).

Therefore, the factored form of the expression 25x^2 - 60x + 36 is indeed (5x - 6)(5x - 6).