what is the average acceleration between 0.0seconds and 2.0seconds of an object whose velocity is constantly decreasing from 10m/s at time 0.0seconds to -10m/s at 2.0seconds.
a = change in velocity/ change in time = -20/2 m/s^2
To find the average acceleration between 0.0 seconds and 2.0 seconds, we need to determine the change in velocity and the time interval.
Given:
Initial velocity, u = 10 m/s
Final velocity, v = -10 m/s
Time interval, t = 2.0 seconds
Step 1: Calculate the change in velocity
Change in velocity = Final velocity - Initial velocity
Δv = v - u = -10 m/s - 10 m/s = -20 m/s
Step 2: Calculate the average acceleration
Average acceleration = Change in velocity / Time interval
a = Δv / t = -20 m/s / 2.0 s = -10 m/s²
Therefore, the average acceleration between 0.0 seconds and 2.0 seconds is -10 m/s².
To calculate the average acceleration, you need to know the change in velocity and the time interval. In this case, the change in velocity is from 10 m/s to -10 m/s, and the time interval is from 0.0 seconds to 2.0 seconds.
To find the change in velocity, you can subtract the initial velocity from the final velocity:
Change in velocity = Final velocity - Initial velocity
Change in velocity = (-10 m/s) - (10 m/s)
Change in velocity = -20 m/s
Next, you need to calculate the time interval:
Time interval = Final time - Initial time
Time interval = 2.0 s - 0.0 s
Time interval = 2.0 s
Now that you have the change in velocity and the time interval, you can calculate the average acceleration using the formula:
Average acceleration = Change in velocity / Time interval
Average acceleration = (-20 m/s) / (2.0 s)
Average acceleration = -10 m/s²
Therefore, the average acceleration between 0.0 seconds and 2.0 seconds is -10 m/s².