calculate the timeperiod of simple period of length 0.84m when g =9.8ms-2
isn't there a simple formula for this? time=2pI*sqrt(L/g) ?
To calculate the time period of a simple pendulum, you need to use the formula:
T = 2π√(l/g)
where:
T is the time period (in seconds),
l is the length of the pendulum (in meters), and
g is the acceleration due to gravity (in m/s^2).
In this case, you are given the length of the pendulum (l = 0.84m) and the acceleration due to gravity (g = 9.8 m/s^2).
Let's substitute the given values into the formula:
T = 2π√(0.84/9.8)
To calculate the square root, you can use a calculator or any mathematical software. Taking the square root, we get:
T = 2π√(0.084)
T ≈ 2π * 0.289428485
Now, you can calculate the value of T:
T ≈ 1.81415247 seconds
Therefore, the time period of a simple pendulum with a length of 0.84 meters and under the acceleration due to gravity of 9.8 m/s^2 is approximately 1.814 seconds.