The volume of a cone shaped hole is 16 pi ft^3. If the hole is 3 ft deep, what is the radius of the hole?
volume = (pi)(r^2)(h) all divided by 3
so you are given certain information and have to re-arrange and solve for the radius (r)
16=(3.114159)(r^2)(3) mulitply pi by the 3
16=9.42477(r^2) divide both sides by 9.42477
1.6976 = (r^2) then take the square root of both sides to get the radius : )
V = 1/3 pi r^2h, so
1/3 pi r^2*3 = 16pi
r=4
Ooooppss lost my divide by 3 in the beginning of the question.
Thanks so much Steve for the fast fix : )
No problem. It wasn't meant as a fix (note the timestamp), just my 2-cents worth.
To find the radius of the cone-shaped hole, we can use the formula for the volume of a cone and solve for the radius.
The formula for the volume of a cone is V = (1/3) * π * r^2 * h, where V is the volume, π is pi, r is the radius, and h is the height.
Given that the volume of the cone-shaped hole is 16π ft^3 and the height of the hole is 3 ft, we can substitute these values into the volume formula:
16π = (1/3) * π * r^2 * 3
Simplifying the equation, we have:
16 = r^2
Now, solve for r by taking the square root of both sides of the equation:
r = √16
The square root of 16 is 4, so the radius of the hole is 4 ft.