A metal bar of mass 100g is warmed from 20°c to 80°c. How much heat is absorbed by the metal bar if the specific heat capacity of this metal is 450J/Kg K.
The equation for specific heat capacity = E = m × c × θ
E = 100g x 450J/Kg x 60° (the temperature change) = 2,700,000J
Q=mc(change In tempreture)
Q=0.1kg*450J/kg.k*60k
Q=2700J
2700j
Correct!
To calculate the heat absorbed by the metal bar, you can use the equation:
Q = mcΔT
Where:
Q is the heat absorbed or released by the object,
m is the mass of the object,
c is the specific heat capacity of the material, and
ΔT is the change in temperature.
In this case, the mass of the metal bar is given as 100g, which is equal to 0.1 kg. The specific heat capacity of the metal is given as 450 J/kg K. And the change in temperature, ΔT, is (80°C - 20°C) = 60°C = 60 K.
Now, you can substitute these values into the equation to calculate the heat absorbed:
Q = (0.1 kg) * (450 J/kg K) * (60 K)
Multiplying these values together, you get:
Q = 2700 J
Therefore, the metal bar absorbs 2700 Joules of heat.
E=100g×450J/kg×60°
E=2,700,000J
Hmmmm E = 100g x 450J/Kg x 60°
E = .1kg x 450J/Kg x 60°=2700Joules