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Question: Ed and Annie are ice skating. Ed (55 kg) and Annie (40kg) both wearing skates face each other at ...

Ed and Annie are ice skating. Ed (55 kg) and Annie (40kg) both wearing skates face each other at rest on a skating rink. Ed pushes Annie sending her eastward with a speed of 4.5m/s. Neglecting friction and air resistance determine the subsequent velocity of Ed. Clearly justify your method of solution (state the principle of physics you are using etc)

momentum before = 0

so
55 Ved + 40 *4.5 = 0 conservation of momentum

To determine the subsequent velocity of Ed after he pushes Annie, we can use the principle of conservation of momentum.

According to the principle of conservation of momentum, the total momentum of a closed system remains constant if no external forces act on it.

In this scenario, Ed and Annie form a closed system as there are no external forces acting on them (neglecting friction and air resistance).

The total momentum before Ed pushes Annie is zero since they are both initially at rest. Therefore, after Ed pushes Annie, the total momentum of the system should still be zero.

Let's denote the velocity of Ed after he pushes Annie as V_ed. The velocity of Annie after being pushed by Ed is 4.5 m/s in the eastward direction. Since the total momentum should be zero, we can write the following equation:

(55 kg)(V_ed) + (40 kg)(4.5 m/s) = 0

Solving this equation will give us the subsequent velocity of Ed after pushing Annie.

(55 kg)(V_ed) = -(40 kg)(4.5 m/s)

Dividing both sides by 55 kg:

V_ed = -(40 kg)(4.5 m/s) / 55 kg

Calculating these values:

V_ed = -3.27 m/s

Therefore, the subsequent velocity of Ed after he pushes Annie is approximately -3.27 m/s (negative sign indicating that Ed moves in the opposite direction of Annie).

Note: The negative sign in front of the velocity indicates that Ed moves in the opposite direction of Annie after the push.