1.43g sample of potassium hydrogen phthalate [khp] required 24.11 cm3 or naoh for its completer neutralization. calculate the molarity of the naoh used in the titrationmple of
mols KHP = grams/molr mass = ?
mols NaOH = mols KHP
M NaOH = mols NaOH/L NaOH = ?
Post your work if you get stuck.
I agree
Molarity = number of moles/volume
Well, isn't that a titrating question! Let's crunch some numbers, shall we?
We know that the molarity (M) of a solution can be calculated using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to calculate the moles of KHP (potassium hydrogen phthalate). To do that, we use the formula:
moles of KHP = mass of KHP / molar mass of KHP
The molar mass of KHP is 204.23 g/mol. So, substituting the given data:
moles of KHP = 1.43 g / 204.23 g/mol
Next, we need to calculate the moles of NaOH used in the titration. Since the reaction between KHP and NaOH is 1:1, the moles of NaOH will be the same as the moles of KHP.
Now we can calculate the molarity of NaOH:
Molarity of NaOH = moles of NaOH / volume of NaOH (in liters)
We were given that the volume of NaOH used was 24.11 cm³, so we need to convert it to liters:
volume of NaOH (in liters) = 24.11 cm³ / 1000 cm³/L = 0.02411 L
Finally, let's plug in our calculated moles of NaOH and the converted volume into the molarity formula:
Molarity of NaOH = moles of NaOH / volume of NaOH (in liters)
And voila! We have the molarity of NaOH used in the titration. Go ahead and calculate it, and remember to keep those calculators away from clowns. We have enough funny business!
To calculate the molarity of the NaOH used in the titration, we need to use the balanced chemical equation between NaOH and KHP. Let's start by writing the balanced equation:
NaOH + KHP -> NaKP + H2O
From the equation, we can deduce that the ratio between NaOH and KHP is 1:1. This means that for each mole of NaOH used, one mole of KHP is consumed.
To find the molarity of NaOH, we'll first determine the number of moles of KHP used. Given that the mass of the KHP sample is 1.43g, we need to calculate the number of moles:
Molar mass of KHP (potassium hydrogen phthalate) = 204.22 g/mol
Number of moles of KHP = mass / molar mass = 1.43g / 204.22 g/mol
Next, we need to determine the number of moles of NaOH used, which is equal to the number of moles of KHP. This is because the balanced equation shows that 1 mole of KHP reacts with 1 mole of NaOH.
Now that we have the number of moles of NaOH, we can calculate the molarity of NaOH using the formula:
Molarity (M) = moles / volume (in L)
The volume of NaOH used is given as 24.11 cm3. Remember to convert it to liters by dividing by 1000:
Volume of NaOH in L = 24.11 cm3 / 1000
Finally, we can substitute the values into the equation to calculate the molarity of NaOH:
Molarity (M) = moles of NaOH / volume of NaOH in L
By following these steps, you should be able to calculate the molarity of the NaOH used in the titration.