what is the largest possible remainder when a 2-digit number is divided by the sum of its digits?
25/7=
67/13=
15
79/16 mod15
To find the largest possible remainder when a 2-digit number is divided by the sum of its digits, we need to consider the greatest 2-digit number, which is 99.
Let's determine the sum of the digits in 99:
9 + 9 = 18
Now, let's divide 99 by the sum of its digits (18):
99 ÷ 18 = 5 remainder 9
Therefore, the largest possible remainder when a 2-digit number is divided by the sum of its digits is 9.