If 3.30 mL of vinegar needs 42.5 mL of 0.150 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in a 1.50 qt sample of this vinegar?
acetic acid = HAc
mols NaOH = M x L = ?
mols NaOH = mols HAc
grams HAc in 3.30 mL = mols HAc x molar mass HAc
Now convert grams in 3.30 mL to grams in 1.qt like this.
grams in 3.30 mL x (1 qt/1,057 mL) = ?
Post your work if you run into trouble.
Well, it seems like you've got quite the pickle here! Let's see if we can help out.
To solve this problem, we'll need to use stoichiometry and some clown math. Are you ready for that? Brace yourself!
First, let's convert the given volume of vinegar (1.50 qt) into mL. Since there are 946.35 mL in 1 qt, we multiply 1.50 qt by 946.35 mL/qt to get 1,419.525 mL of vinegar. Hang in there!
Now, we can set up a proportion using the volume of NaOH needed to reach the equivalence point:
3.30 mL of vinegar is to 42.5 mL of NaOH as 1,419.525 mL of vinegar is to x grams of acetic acid.
Let's do some circus math:
(3.30 mL / 42.5 mL) = (1,419.525 mL / x grams)
Cross-multiplying and solving for x:
x = (1,419.525 mL * 42.5 mL) / 3.30 mL
After all the juggling, we find that x = 18,433.586 grams of acetic acid in your 1.50 qt sample of vinegar.
So, there you have it - a whopping 18,433.586 grams of acetic acid! That's a lot of vinegar! I hope that helps, and remember, don't clown around too much in the lab!
To find the number of grams of acetic acid in a 1.50 qt sample of vinegar, we need to follow these steps:
Step 1: Convert the volume of vinegar from quarts to milliliters.
1 quart = 946.35 mL (conversion factor)
Given: 1.50 qt
1.50 qt * 946.35 mL/qt = 1419.53 mL
Therefore, the volume of vinegar is 1419.53 mL.
Step 2: Set up a proportion to find the number of moles of acetic acid in the vinegar.
From the titration, we know that 3.30 mL of vinegar reacts with 42.5 mL of 0.150 M NaOH. We can use this information to calculate the moles of acetic acid.
Volume of vinegar (in mL) / Volume of NaOH (in mL) = Moles of acetic acid / Moles of NaOH
3.30 mL / 42.5 mL = Moles of acetic acid / (0.150 M NaOH * 42.5 mL)
Simplifying the equation:
3.30 mL * (0.150 M NaOH * 42.5 mL) = 42.5 mL * Moles of acetic acid
Moles of acetic acid = 3.30 mL * 0.150 M NaOH / 42.5 mL
Moles of acetic acid = 0.0117 mol
Therefore, there are 0.0117 moles of acetic acid in 3.30 mL of vinegar.
Step 3: Calculate the number of grams of acetic acid in the 1.50 qt sample of vinegar.
To calculate the number of grams, we need to use the molar mass of acetic acid, which is 60.05 g/mol.
Grams of acetic acid = Moles of acetic acid * Molar mass
Grams of acetic acid = 0.0117 mol * 60.05 g/mol
Grams of acetic acid = 0.700 g
Therefore, there are approximately 0.700 grams of acetic acid in a 1.50 qt sample of this vinegar.
To find the number of grams of acetic acid in the given vinegar sample, we can use the concept of stoichiometry and the information provided in the question.
First, let's convert the given volume of vinegar from quarts to milliliters:
1.50 qt * 946.3529 mL/qt = 1419.53 mL (rounded to four decimal places)
Next, we can set up a proportion using the volume of vinegar and the volume of NaOH required to reach the equivalence point:
3.30 mL of vinegar / 42.5 mL of NaOH = 1419.53 mL of vinegar / x mL of NaOH
Now, solving for x, we can rearrange the equation:
x = (42.5 mL of NaOH * 1419.53 mL of vinegar) / 3.30 mL of vinegar
Calculating this expression gives:
x ≈ 1830.0323 mL of NaOH
Since the number of moles of acetic acid is equal to the number of moles of NaOH (as they react in a 1:1 ratio), we can use the concentration of NaOH in moles per liter (M) to find the number of moles of acetic acid in the vinegar sample.
First, convert 1830.0323 mL of NaOH to liters:
1830.0323 mL * 1 L/1000 mL = 1.8300323 L
Now, we can calculate the number of moles of acetic acid using the equation:
moles of acetic acid = volume of NaOH (in liters) * concentration of NaOH
moles of acetic acid = 1.8300323 L * 0.150 moles/L
Calculating this expression gives:
moles of acetic acid ≈ 0.2745048 moles
Finally, we can find the mass of acetic acid in grams by multiplying the number of moles by the molar mass of acetic acid, which is 60.052 g/mol:
mass of acetic acid = moles of acetic acid * molar mass of acetic acid
mass of acetic acid = 0.2745048 moles * 60.052 g/mol
Calculating this expression gives:
mass of acetic acid ≈ 16.4764 g
Therefore, there are approximately 16.4764 grams of acetic acid in a 1.50 quart sample of the given vinegar.